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Jeriel leans a 26 foot ladder against a wall so that it forms an angle of 61 with the ground .

Jeriel leans a 26 foot ladder against a wall so that it forms an angle of 61 with-example-1

1 Answer

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To solve this problem we will use the following diagram:

where d is the distance between the base of the ladder and the wall.

Using the cosine we get:


\cos 61^(\circ)=(d)/(26ft).

Multiplying the above equation by 26ft we get:


\begin{gathered} \cos 61^(\circ)*26ft=(d)/(26ft)*26ft\text{.} \\ d=26ft\cdot\cos 61^(\circ)\text{.} \end{gathered}

Then:


d\approx12.60505013ft\approx12.61ft.

Answer: 12.61.

Jeriel leans a 26 foot ladder against a wall so that it forms an angle of 61 with-example-1
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