Question

P and Q are points within a uniform electric field that are separated by a distance of 0.2 m as shown. The potential difference between P and Q is 75 V.How much work is required to move a +150 μC point charge from P to Q?0.023 J140 J0.011 J2800 J75 J

Answer 1

0.011 J

Explanation:

Given:

q = 150 μC

v = 75 V

r = 0.2

We calculate the work as the product between the charge and the potential difference, just like this:

`\begin{gathered} W=q\cdot v \\ W=150\cdot10^(-6)\cdot75 \\ W=0.01125\text{ J} \\ W\cong0.011\text{ J} \end{gathered}`

The work required is 0.011 J