Question

C(n) = -6 (-1/3) *n-1What is the 2nd term in the sequence ?

Answer 1

We are given the following sequence

`c(n)=-6(-(1)/(3))^(n-1)`

We are asked to find the 2nd term of the above sequence

Let us substitute n = 2 into the given sequence

`\begin{gathered} c(2)=-6(-(1)/(3))^(2-1) \\ c(2)=-6(-(1)/(3))^1 \\ c(2)=6\cdot(1)/(3) \\ c(2)=2 \end{gathered}`

Therefore, the 2nd term of the given sequence is 2