Question

Find the 12th term in the arithmetic sequence an = 3 − 6(n − 1)a. -33b. -36c. -63d. -69

Answer 1

-63

Explanation:

Answer 2

Given:

`a_n=3-6(n-1)`

Find-: 12th term of the sequence is

Sol:

`\begin{gathered} a_n=3-6(n-1) \\ \end{gathered}`

Where,

`\begin{gathered} n=\text{ term.} \\ \\ n=12 \end{gathered}`

Put the value then:

`\begin{gathered} a_n=3-6(n-1) \\ \\ n=12 \\ \\ a_(12)=3-6(12-1) \\ \\ a_(12)=3-6(11) \\ \\ a_(12)=3-(6*11) \\ \\ a_(12)=3-66 \\ \\ a_(12)=-63 \end{gathered}`

So 12th term is -63