Question

Emanuel can throw a baseball 22 miles per hour. He throws the ball straight up in the air, releasing it at 5.6 feetabove the groundThe equation that represents the approximate height of the ball during the seconds after it is thrown ish - 16t? + 32.3t +5.6.If h represents height in feet, and t represents time in seconds, approximately how high is the ball 1.5 seconds afterit is thrown?

Answer 1

The height equation is H = -16t^2 + 32.3t + 5.6.

Substitute 1.5 for t in the equation to determine the height of the ball after 1.5 second.

`\begin{gathered} H=-16(1.5)^2+32.3\cdot1.5+5.6 \\ =-36+48.45+5.6 \\ =18.05 \end{gathered}`

So height is 18.05 feet.