Question

21. A truck is driving N35oE at a speed of 110 km/h. Determine the components of the vector representing this force.

Answer 1

The question will be represented below as

To figure out the horizontal component (x), we will use the trigonometric ratio below

`\begin{gathered} sin\theta=(opp)/(hyp) \\ \theta=35^0,opp=x,hyp=110 \end{gathered}`

By substituting the values, we will have

`\begin{gathered} s\imaginaryI n\theta=(opp)/(hyp) \\ sin35=(x)/(110) \\ x=110\sin35^0 \\ x=63.1\text{ km/h} \end{gathered}`

Step 2:

To figure out the vertical component (y), we will use the trigonometric ratio below

`\begin{gathered} \cos\theta=(adj)/(hyp) \\ \theta=35^0,adj=y,hyp=110 \end{gathered}`

By substituting the values, we will have

`\begin{gathered} \cos(\theta)=(adj)/(hyp) \\ \cos35=(y)/(110) \\ y=110cos35^0 \\ y=90.1 \end{gathered}`

Hence,

The horizontal component is = 63.1 km/h

The vertical component is = 90.1 km/h