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The power company routes its lines as shown in the illustration. How much wire ( in yards) could be saved by going directly from A to E? yd

The power company routes its lines as shown in the illustration. How much wire ( in-example-1
User Bountiful
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1 Answer

4 votes

To solve this question we will use the following diagram:

Using the Pythagorean theorem for triangle AEO we get:


AE^2=AO^2+EO^2\text{.}

Substituting AO=68 yd, and EO=285 yd we get:


\begin{gathered} AE^2=(68yd)^2+(285yd)^2, \\ AE^2=4624yd^2+84225yd^2, \\ AE^2=85849yd^2, \\ AE^2=293^2yd^2\text{.} \end{gathered}

Therefore AE=293 yd. Now, the wire required for the long path is:


38yd+304yd+30yd+19yd=391yd\text{.}

Therefore you could save:


391yd-293yd=98yd

taking the short route.

Answer: 98yd.

The power company routes its lines as shown in the illustration. How much wire ( in-example-1
User GodLesZ
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