Question

Vera wants to prove that any rectangle is also a parallelogram

Answer 1

The correct statement to prove that rectangle ABCD is a parallelogram is: In Quadrilateral ABCD, If m∠A = m∠B = m∠C = m∠D = 90°, then AB ║ DC and AD ║ BC

How to prove that any rectangle is also a parallelogram?

We know that rectangles and parallelograms share some similarities and as such:

Each pair of co-interior angles are supplementary, because two right angles add to a straight angle, so the opposite sides of a rectangle are parallel. This means that a rectangle is a parallelogram, so: Its opposite sides are equal and parallel. Its diagonals bisect each other.

Thus, the correct statement to prove that rectangle ABCD is a parallelogram is:

In Quadrilateral ABCD, If m∠A = m∠B = m∠C = m∠D = 90°, then AB ║ DC and AD ║ BC

Answer 2

We are given a rectangle ABCD

Recall that a rectangle is a quadrilateral in which all angles are right angles (90°)

Each pair of interior angles are supplementary. The two right angles add to a straight angle which means that the opposite sides of a rectangle are parallel.

In quadrilateral ABCD, if m∠A = m∠B = m∠C = m∠D = 90° then AB || DC and AD || BC

Hence, a rectangle is also a parallelogram.

Option B is the correct answer.