Question

I need help with my homework the question comes in 4 parts

Answer 1

The function of the quadratic equation in vertex form is given below as

`f(x)=7(x_{}+1)^2-9`

From the graph of the function above, we can see that the leading coefficient is greater than zero ,

Hence,

The graph opens up

Part B:

To figure out the vertex of the graph, we will use the general form of a quadratic function given below as

`f(x)=a(x-h)^2+k`

By comparing coefficients, we will have

`\begin{gathered} f(x)=a(x-h)^2+k \\ f(x)=7(x+1)^2-9 \\ a=7,h=-1,k=-9 \end{gathered}`

The coordinates of the vertex is represented below as

`(h,k)\Rightarrow(-1,-9)`

Hence,

The vertex of the graph in ordered pair is = ( -1. -9)