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Solve the equation.3(3y-1)-3(2y)=2

User Ddidier
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1 Answer

4 votes

Given the equation:

3(3y-1)-3(2y)=2

To solve, the first step is to expand the parentheses:


(3\ast3y)\text{ - (3}\ast1)\text{ - (3}\ast2y)\text{ = 2}
9y\text{ - 3 - 6y = 2}

Now, collect the like terms on the left hand side of the equation:


9y\text{ - 6y - 3 = 2}
3y\text{ - 3 = 2}

Add 3 to both sides of the equation:


3y\text{ - 3 + 3 = 2 + 3}
3y\text{ = 5}

Now divide both sides by 3:


(3y)/(3)\text{ = }(5)/(3)
\begin{gathered} y\text{ = }(5)/(3) \\ or\text{ } \\ y\text{ = 1.67} \end{gathered}

User BaptWaels
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