Question

There are 4 consecutive integers that have a sum of 42. What is the value of the leastinteger?

Answer 1

Given :

There are 4 consecutive integers

Let the numbers are :

`x,(x+1),(x+2),(x+3)`

The sum of the numbers are 42

so,

`x+(x+1)+(x+2)+(x+3)=42`

Combine the like terms :

`\begin{gathered} 4x+6=42 \\ 4x=42-6 \\ 4x=36 \\ \\ x=(36)/(4)=9 \end{gathered}`

So, the value of the least integer = 9