Given that the fundamental frequency of the string is f = 200 Hz
We have to find the second overtone frequency.
The second overtone frequency can be calculated by the formula
![f_2=3f](https://img.qammunity.org/2023/formulas/physics/college/ye7rwm3fs0mzfc0zxrzhm5xgu0aaj55m2w.png)
Substituting the value, the frequency of the second overtone is
![\begin{gathered} f_2=3*200 \\ =600\text{ Hz} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/72mx6vzf4jbx40jumrdc4f1y42j9z7im1q.png)
Thus, the second overtone frequency is 600 Hz.