Question

Assume that each of the n trials is independent and that p is the probability of success on a given trial. Use the binomial probability formula to find P(x).nequals=66, xequals=11, pequals=0.30.3Question content area bottomPart 1P(x)equals=   enter your response here (Round to 4 decimal places.)

Answer 1

Step-by-step explanation

The binomial probability distribution formula is given as

`P(x)=(n!)/((n-x)!x!)p^xq^(n-x)`

From the question, we have that n=6, x =1 and p =0.3. Hence, q = 1-p =0.7

Therefore, we will have that

`\begin{gathered} P(1)=(6!)/((6-1)!1!)(0.3)^1(0.7)^(6-1) \\ P(1)=(6!)/(5!1!)(0.3)(0.7)^5 \\ =(6*5!)/(5!*1)(0.3)(0.7)^5 \\ =6(0.3)(0.7)^5 \\ =0.3*\:1.00842 \\ =0.3025 \end{gathered}`

Answer: 0.3025