Question
The probability that a student takes an English class and a math class is 0.084. The probability that a student takes an English class is 0.49. What is the probability that a student takes a math class, given that the student is taking an English class?
Solution
Let E denotes the event that the student takes an English class
Let M denotes the event that the student takes a Math class
We are given
![\begin{gathered} p(E\cap M)=0.084 \\ p(E)=0.49 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/hx2mgcxcbyhm1fj4e082x00z5o9ej3lujk.png)
We want to find
![p(M|E)](https://img.qammunity.org/2023/formulas/mathematics/college/kaq05bmvjm8vx4jmqb6el21gn0xvt1msqo.png)
The formula to use is given as
![p(M|E)=(p(M\cap E))/(p(E))](https://img.qammunity.org/2023/formulas/mathematics/college/kchmf44jqihodkorexuix343q0m7rezw2z.png)
![\begin{gathered} p(M|E)=(p(M\cap E))/(p(E)) \\ p(M|E)=(0.084)/(0.49) \\ p(M|E)=0.1714 \\ p(M|E)=0.171 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/bceuxzveqz48xpvwl3juhb3nkvwa532ex9.png)
Thus, the answer is 0.171
Option D