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Val Bakhtin · Answer 1 · 2023-03-13T16:12:28+0000

We are given the diagrams:

We are required to find the length of AC

When two triangles are similar, the ratio of their corresponding sides are congruent.

Hence, we can write:

$(AC)/(6)\text{ = }(20)/(12)$

Solving for AC:

$\begin{gathered} Cross-Multiply \\ AC\text{ }*\text{ 12 = 6 }*\text{ 20} \\ Divide\text{ both sides by 12} \\ AC\text{ = }\frac{6\text{ }*20}{12} \\ =\text{ 10} \end{gathered}$

Answer: 10

Similar triangle homework written ex #4-6 even and 14-16 even Answer question 4-example-1

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