Question

Similar triangle homework written ex #4-6 even and 14-16 even Answer question 4

Answer 1

We are given the diagrams:

We are required to find the length of AC

When two triangles are similar, the ratio of their corresponding sides are congruent.

Hence, we can write:

`(AC)/(6)\text{ = }(20)/(12)`

Solving for AC:

`\begin{gathered} Cross-Multiply \\ AC\text{ }*\text{ 12 = 6 }*\text{ 20} \\ Divide\text{ both sides by 12} \\ AC\text{ = }\frac{6\text{ }*20}{12} \\ =\text{ 10} \end{gathered}`

Answer: 10