Given data:
* The force applied on the box is,

* The mass of the box is m = 35 kg.
* The distance traveled by the box is d = 14 m.
* The coefficient of kinetic friction is,

Solution:
The normal force acting on the box is,

where g is the acceleration due to gravity,
Substituting the known values,

The kinetic frictional force acting on the box is,

Substituting the known values,

The net force acting on the box in terms of applied force and frictional force is,

Thus, the work done in accelerating the box is,

Thus, the work done in accelerating the box is 9279.2 J or approximately 9.3 kJ.