In order to calculate how many students played one or more of the three sports, we can use the formula below:
![N(B\cup V\cup S)=N(B)+N(V)+N(S)-N(B\cap V\text{ only})-N(V\cap S\text{ only})-N(B\cap S\text{ only})-2N(B\cap V\cap S)](https://img.qammunity.org/2023/formulas/mathematics/college/qtadzgfjkibqryg8dfpzhzb0pmixgjtmdg.png)
From the given information, we have:
N(B) = 25
N(V) = 22
N(S) = 23
N(B and V only) = 2
N(V and S only) = 3
N(B ans S only) = 1
N(B and V and S) = 6.
So we have:
![N(B\cup V\cup S)=25+22+23-2-3-1-12=52](https://img.qammunity.org/2023/formulas/mathematics/college/tgnk05rkq8o3bvify6pl5mngj83bs8tn33.png)
Therefore the number of students that play at least one sport is 52.