The question tells us there is a rolling die with 6 faces.
This means that the probability of getting any number after rolling the die is equal for all values of die.
i.e.
![\begin{gathered} P(\text{any value on die)=}(1)/(6) \\ \\ i\mathrm{}e\text{.} \\ P(1)=(1)/(6) \\ P(2)=(1)/(6) \\ P(3)=(1)/(6) \\ \\ \ldots\text{and so on} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/tperk4d0v8go5xb26orboniubhrcixg1an.png)
The number of cards in the deck is: 5 red + 7 blue + 8 yellow = 20 cards altogether.
Thus, if we pick a blue card from this deck of 20 cards, the probability is:
![\begin{gathered} P(\text{blue)}=\frac{n\text{umber of blue cards}}{\text{total number of cards}} \\ \\ P(\text{blue)}=(7)/(20) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/12dura2ild9epmlbrruyrajb1cwziprckr.png)
Therefore, if these two events - rolling a die and picking a blue card - occur at the same time, then we use the AND probability to solve.
This is done below:
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