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What are the real and complex solutions(roots) of the polynomial equationX^3-27=0

User Waj
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1 Answer

5 votes

Given the following equation:


\text{ x}^3\text{ - 27 = 0}

Let's determine its solution.

We get,


\text{ x}^3\text{ - 27 = 0}
\text{ x}^3\text{ = 27}
\text{ }\sqrt[3]{\text{x}^3}\text{ = }\sqrt[3]{\text{27}}
\text{ x = 3}

Therefore, the answer is x = 3.

User Jiamo
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