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Compute 2x^5-x^4+3x^2-x+5÷x-1

1 Answer

4 votes

we have

2x^5-x^4+3x^2-x+5 ÷ (x-1)

2x^4+x^3+x^2+4x+3

-2x^5​+2x^4

----------------------------

x^4+3x^2-x+5

-x^4+x^3

--------------------

x^3+3x^2-x+5

-x^3+x^2

--------------------

4x^2-x+5

-4x^2+4x

---------------------

3x+5

-3x+3

------------

8 --------> remander

therefore

2x^5-x^4+3x^2-x+5 =(x-1)(2x^4+x^3+x^2+4x+3)+8

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