The diagram represents a right-angled triangle and we are given the following sides
AB=6
AC=4.9
BC=?
METHOD 1
We can write an expression for BC using the Pythagoras theorem below:
![\begin{gathered} AB^2=AC^2+BC^2 \\ BC^2=AB^2-AC^2 \\ BC=\sqrt[]{AB^2-AC^2} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/vygkrr6wosadh5thy8thspcxutmefe0d1l.png)
Therefore the expression is
![BC=\sqrt[]{AB^2-AC^2}](https://img.qammunity.org/2023/formulas/mathematics/college/4zmwdj2tj8dkmjehw8f3qotr7fv43oie8d.png)
The expression can be further solved to get BC
![\begin{gathered} AB^2=AC^2+BC^2 \\ 6^2=4.9^2+BC^2 \\ 36=24.01+BC^2 \\ BC^2=36-24.01 \\ BC^2=11.99 \\ BC^2=\sqrt[]{11.99} \\ BC=3.46 \\ \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/4po8jg4fmizm9fb9xm6arp54njvwf0tynt.png)
METHOD 2
The second expression can be gotten using SOHCAHTOA:
Since we are given the opposite side and the hypotenuse we would make use of
CAH

Therefore the expression is

The expression can be further solved to get BC

We can clearly see that both methods give a very similar answer. Therefore the expressions are correct