Question

Write the equation of the line that has a slope of-2/3 and passes through the point (3, 10)

Answer 1

Given:

The slope of the line = m = -2/3

The line passes through the point (3, 10)

We will write the equation of the line with the point-slope form:

`\begin{gathered} y-k=m\cdot(x-h) \\ y-10=-(2)/(3)(x-3) \end{gathered}`

Convert the point-slope form into the slope-intercept form

Solve the equation for y

`\begin{gathered} y-10=-(2)/(3)x-(2)/(3)\cdot(-3) \\ y-10=-(2)/(3)x+2 \\ y=-(2)/(3)x+2+10 \\ \\ y=-(2)/(3)x+12 \end{gathered}`

so, the answer will be:

`y=-(2)/(3)x+12`