Question

5. You are a fermenting glucose to make wine, and notice at Noon that 730 mL of CO2 gas was produced at 37°C and 1 atm pressure in your system. What would the final volume in liters) of the gas produced be whenyou measured later that evening at 26 °C and 660 mmHg, if the amount of gas did not change? 3 ptsyea

Answer 1

The final volume of the gas is 0.81L.

Step-by-step explanation:

1st) It is necessary to write all the variables given before start, and make sure that volume is in L, the temperature in K, and the pressure in atm, to use the ideal gas equation properly:

Variables at noon:

• V1: 730mL (0.73L)

• T1: 37 °C (310.15K)

• P1: 1atm

Variables at evening:

• V2: this is the volume that we have to calculate.

• T2: 26°C (299.15K)

• P2: 660mmHg (0.87atm)

2nd) Now we can replace the values in the formula and calculate the final volume:

`\begin{gathered} (P_1*V_1)/(T_1)=(P_2*V_2)/(T_2) \\ (1atm*0.73L)/(310.15K)=(0.87atm*V_2)/(299.15K) \\ 0.002354(atm*L)/(K)=0.002908(atm)/(K)*V_2 \\ (0.002354)/(0.002908)L=V_2 \\ 0.81L=V_2 \end{gathered}`

So, the final volume of the gas is 0.81L.