Question

A ball is dropped from a 70-m building. The height (in meters) after t sec is given by h (t) =-4.9t^2+ 70.(a) Find h(1) and h (1.5).(b) Interpret the meaning of the function values found in part (a).Part: 0 / 4Part 1 of 4) (a) h(1)=0xХ5立

Answer 1

Given the Quadratic Function:

`h(t)=-4.9t^2+70`

(a) You need to substitute this value of "t" into the function and evaluate:

`t=1`

In order to find:

`h(1)`

Then, you get:

`h(1)=-4.9(1)^2+70`
`h(1)=65.1`

You need to substitute this value of "t" into the function and evaluate:

`t=1.5`

In order to find:

`h(1.5)`

Then, you get:

`h(1.5)=-4.9(1.5)^2+70`
`h(1.5)=58.975`

(b) You know that "h" represents the height of the ball after it is dropped (in meters) and "t" represents the time (in seconds) after it is dropped. Therefore:

1. Having this function value:

`h(1)=65.1`

You can conclude that, after 1 second, the height of the ball is:

`65.1\text{ }meters`

2. Having this function value:

`h(1.5)=58.975`

You can conclude that, after 1.5 seconds, the height of the ball is:

`58.975\text{ }meters`

Hence, the answers are:

(a)

`h(1)=65.1`

`h(1.5)=58.975`

(b) - Interpretation for this function value:

`h(1)=65.1`

After 1 second, the height of the ball is:

`65.1\text{ }meters`

- Interpretation for this function value:

`h(1.5)=58.975`

After 1.5 seconds, the height of the ball is:

`58.975\text{ }meters`