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2 votes
Solve sin2x-sin4x +sin6x=0

User Labjunky
by
7.8k points

1 Answer

5 votes

Remember that


\sin 2\theta=2\sin \theta\cos \theta

Therefore,


\begin{gathered} \sin 2x-\sin 4x+\sin 6x=0 \\ \Rightarrow2\sin x\cos x-2\sin 2x\cos 2x+2\sin 3x\cos 3x=0 \end{gathered}

Then,


undefined

User Kartik Shandilya
by
8.1k points

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