Question

In one classroom homework is worth 25% of the final grade, each of the three projects is worth 10%, and the final exam is worth 45%. If student has an 87 on a homework average and a 94 on the first project, what is the students grade at this point if that same student from part a gets a 71 on the second project and a 78 on the third project what is the lowest grade the student can get on the final exam to get an 80 over on the course

Answer 1

• a) 30.9

,

• b) 76

Step-by-step explanation

Given

• Homework: 25%

,

• Project: 10% (each)

,

• Final exam: 45%

A student has:

Part A

• Homework: 86

,

• First project: 94

Part B

• Second project: 71

,

• Third project: 78

,

• Total grade: 80

Procedure

• a)

To know the student's grade at the point where he has an 86 homework average and 94 on the first project. We have to multiply the ponderation of each category times the grade to find the final grade (TG), meaning:

`TG=86(0.25)+94(0.10)`

Simplifying:

`TG=21.5+9.4`
`TG=30.9`

• b)

Following the same procedure, now we have to multiply the ponderations of the new grades, as follows:

`TG=FE+30.9+71\cdot(0.1)+78\cdot(0.1)`
`TG=FE+30.9+7.1+7.8`
`TG=FE+45.8`

Next, as we are asked to find the calculations of the grade of the exam to get a final grade of 80, we have to consider the latter and the ponderation for the exam:

`80=x\cdot0.45+45.8`

where x is the grade of the exam.

Solving for x:

`x=(80-45.8)/(0.45)`
`x=76`