A lamp draws 3 amperes of current and is connected to a 120 volt supply.
We are asked to find the resistance of the lamp.
Recall the Ohm's law is given by
![V=IR](https://img.qammunity.org/2023/formulas/physics/college/qyxkyhe6das1rxrn37kfxfu7hnf52d3137.png)
Where V is the voltage, I is current, and R is the resistance.
Re-arrange the equation for resistance
![R=(V)/(I)](https://img.qammunity.org/2023/formulas/physics/college/58rgrjooatmu3x2o7lod65zu15oehjjsfu.png)
Substitute the given values
![\begin{gathered} R=(120)/(3) \\ R=40\; \Omega \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/3ztl6j5hr45ecuywdta5n5jb42yy4i4und.png)
Therefore, the resistance of the lamp is 40 ohms.