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Find the area of the rectangle that has a perimeter of 8x − 14 units and a length of x − 5 units.

User Akaspick
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Answer: Area = 4 square units

Perimeter of the rectangle = 8x - 14 units

Length of the rectangle = x - 5 units

Let the width of the rectangle = x units

Perimeter = 2( length + width)

8x - 14 = 2(x - 5 + x)

Solve the parenthesis for once

8x - 14 = 2(x + x - 5)

8x - 14 = 2(2x - 5)

8x - 14 = 4x - 10

Collect the like terms

8x - 4x = -10 + 14

4x = 4

Divide both sides by 4

4x/4 = 4/4

x = 1

Since, the length is x - 5 units

Length = 1 - 5

Length = - 4units

Length = 4 units

Width = 1 unit

Area = length x width

Area = 4 x 1

Area = 4 square units

User Jose Manuel
by
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