Step-by-step explanation
Given the exponential function:
45(1.085)^t
We have that 45=a is the initial value and 1.085 is the growth rate,
1.085 - 1 = 0.085* 100 = 8.5 % (This is the growth rate)
Let's compute the function with two values of t, as for instance, t=0 and t=1:
![f(0)=45(1.085)^0=45\cdot1=45\longrightarrow\text{ (0,45)}](https://img.qammunity.org/2023/formulas/mathematics/college/s7uwdqctjekjxlmyij6qi4h2qe8h1aua2m.png)
![f(1)=45\cdot(1.085)^1=48.825\text{ }\longrightarrow\text{(1,48.825)}](https://img.qammunity.org/2023/formulas/mathematics/college/kymfeluawadeo1b1ce3p95b5blyk2ekbet.png)
Now, the function in the form y = ae^kt will be as follows:
![y=45\cdot e^(kt)](https://img.qammunity.org/2023/formulas/mathematics/college/tlu3xo42vge6fqy4p9axt8dkgl3lqrwfzv.png)
Substituting t by 1:
![y(1)=45\cdot e^k=48.825](https://img.qammunity.org/2023/formulas/mathematics/college/agb86g3xs1k18jmmpvy2pn6k3j4pdu22vy.png)
Dividing both sides by 45:
![e^k=(48.825)/(45)=1.085](https://img.qammunity.org/2023/formulas/mathematics/college/di5v5hopnjvp4x2d9sou974ci0nh1xzp7w.png)
Applying ln to both sides:
![k=\ln 1.085](https://img.qammunity.org/2023/formulas/mathematics/college/9epdtvydfsb97ttivrer2i4uasudhtllzr.png)
Computing the argument:
![k=0.0816](https://img.qammunity.org/2023/formulas/mathematics/college/ziugxtz6kqeir4ztt7r389himdmcamqeq0.png)
The expression will be as follows:
![(a)---\longrightarrow y=45e^(0.0816t)](https://img.qammunity.org/2023/formulas/mathematics/college/8zdkae6nert8u29xzfiizlcz2alu9k6ogd.png)
As this is a growing function, the rates are positive.
The annual growth rate is 8.5% and It's was calculated above.
Now, we need to compute the continuous rate because It's given by the value of k:
k = 0.0816 --> Multiplying by 100 --> 0.0816 * 100 = 8.16%
The continuous growth rate is 8.16%