Question

Solve the system of equations.y= x2 + 3x - 4y = 2x - 4A. (-1,6) and (0,4)O B. (-1,-6) and (0, -4)C. (0,-4) and (1, -2)O D. (0,4) and (1,-6)

Answer 1

(0,-4) and (-1,-6) or B

Explanation:

Notice that equation 1 and equation 2 are both equal to y.

Substitute equation 2 into equation 1:

`2x-4=x^2+3x-4`

Simplify:

`x^2+x=0`

Factor:

`x(x+1)=0`

Notice that the zeros for x are x = 0 and x = -1.

Now plug both values into either equation 1 or 2 to find y:

`y=0^2+3(0)-4 = -4`

`y=(-1)^2+3(-1)-4=-6`

Therefore, our values are (0,-4) and (-1,-6) or option B