Question

A torpedo fired from a submerged submarine is propelled through the waterwith a speed of 20.00 m/s and explodes upon impact with a target 2000.0 maway. If the sound of the impact is heard 101.4 s after the torpedo was fired,what is the speed of sound in water? (Because the torpedo is held at a constantspeed by its propeller, the effect of water resistance can be neglected.)

Answer 1

Given,

The initial speed, u=20.00 m/s

The distance between the submerine and the target is d=2000.0m

The sound of impact is heard after T=101.4 s.

To find

The speed of sound in water.

Step-by-step explanation

Here the total time taken to reach the submarine is the sum of thetime taken by the torpedo to reach the target and the time taken for it to come back.

Let the speed be v.

Thus,

`\begin{gathered} T=(d)/(u)+(d)/(v) \\ \Rightarrow101.4=(2000)/(20)+(2000)/(v) \\ \Rightarrow v=1428.6\text{ m/s} \\ \end{gathered}`

Conclusion

Speed of the sound in water is 1428.6 m/s