Question

A solid disc initially rotating at 10rad/sec covers an angular distance of 100 rad at the end of 5sec, what will be the speed of the disc at the end of 10 sec?

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Answer 1

Hi there!

We can begin by solving for the angular acceleration using the kinematic equation:

θ = ωit + 1/2αt²

Plug in known values:

100 = 10(5) + 1/2(α)(25)

100 = 50 + 12.5α

50 = 12.5α

a = 4 rad/sec²

Now, we can use the following equation:

ωf = ωi + αt

Solve:

ωf = 10 + 4(10) = 50 rad/sec