Given:
There are given that the two points:

Step-by-step explanation:
According to the question:
We need to find the equation of the line:
Then,
To find the equation of the line, first, we need to find the slope of the line.
So,
From the formula of the slope of the line:

Where,

Then,
Put all the values into the given formula:
So,

Then,
From the formula of the equation of the line:

Then,
Put the value of m into the above equation:
So,

Then,

Final answer:
Hence, the equation of line is shown below:
