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4 votes
What values of b satisfy 4(3b+2)^2=64

2 Answers

2 votes

Answer: b=2/3 and b=-2

Explanation:

User Naugler
by
3.7k points
5 votes

4(3b+2)^2=64

solve for b:

take the square root of both sides:


\begin{gathered} \sqrt[]{4(3b+2)^2}=\sqrt[]{64} \\ \sqrt[]{4}\cdot\sqrt[]{(3b+2)^2}=\pm8 \\ 2(3b+2)=\pm8 \\ 6b+4=\pm8 \\ so\colon \\ b=(\pm8-4)/(6) \end{gathered}

therefore:


\begin{gathered} b=(2)/(3) \\ or \\ b=-2 \end{gathered}

User Chandresh M
by
3.3k points