Question

A chemist makes 770. mL of barium chloride (BaCl₂) working solution by adding distilled water to 50.0 mL of a 1.74 Mstock solution of barium chloride in water.Calculate the concentration of the chemist's working solution. Round your answer to 3 significant digits.MX5 ?

Answer 1

0.113 M

Step-by-step explanation

Given that:

The volume of the stock solution, V₁ = 50.0 mL

The concentration of the stock solution, C₁ = 1.74 M

The volume of the solution the chemist made, V₂ = 770.0 mL

What to find:

The concentration (C₂) of the BaCl₂ solution the chemist made.

Step-by-step solution:

The concentration (C₂) of the chemist's working solution can be calculated using the dilution formula below:

`\begin{gathered} C_1V_1=C_2V_2 \\ \\ C_2=(C_1V_1)/(V_2)=(1.74M*50.0mL)/(770.0mL) \\ \\ C_2=(87M)/(770.0) \\ \\ C_2=0.113M \end{gathered}`

Hence, the concentration of the chemist's working solution is 0.113 M.