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13 votes
13 votes
What is the 69th term of the following arithmetic sequence 8,17,26,35

User Rafis Ganeev
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2 Answers

20 votes
20 votes

Answer:

the 69th term is 620

Explanation:

Using th explicit formula you get an = 9n-1

then you plug 69 for n and you get 69 x 9 which is 621 and then you subtract one and get 620

User Blotto
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2.7k points
17 votes
17 votes

Answer:

Thus the first 3-digit term of the given arithmetic sequence is 108.

Explanation:

Given:

The arithmetic sequence: 8, 17, 26, 35, ... ...

To find:

The first 3-digit term of the sequence

Step-by-step explanation:

Given, the arithmetic sequence: 8, 17, 26, 35, ... ...

Then the common difference

= 17 - 8 = 26 - 17 = 35 - 26 = ... ... = 6

Now the next terms of the sequence are

35 + 9, 35 + 9 + 9, 35 + 9 + 9 + 9, ... ...

i.e., 35, 45, 54, 63, 72, 81, 90, 99, 108, ... ...

User Jan Slominski
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3.3k points