Question

I’m trying to complete old work but this assignment was some time ago and I do not remember the steps to it

Answer 1

Given:

`\sin\theta=(5)/(13)`

Required:

To find the value of

`\cos2\theta`

Step-by-step explanation:

We know that

`\cos2\theta=1-2\sin^2\theta`
`\begin{gathered} =1-2(\sin\theta)^2 \\ \\ =1-2((5)/(13))^2 \\ \\ =1-2((25)/(169)) \\ \\ =1-(50)/(169) \\ \\ =(169-50)/(169) \\ \\ =(119)/(169) \end{gathered}`

Final Answer:

`\cos2\theta=(119)/(169)`