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63Perimeter of the base =Height of the prism =Area of the base =Lateral Area =u2Surface Area =42 2Volume =3Blank 1:Blank 2:Blank 3:Blank 4:Blank 5:Blank 6:

63Perimeter of the base =Height of the prism =Area of the base =Lateral Area =u2Surface-example-1

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The shape is a trigular base prism

1. The perimeter of the base (triangle)


\begin{gathered} Hyp^2^{}=opp^2+adj^2 \\ \\ \text{Hypo}^2=3^2+4^2 \\ \text{Hypo}^2=9+16 \\ \text{Hypo}^2=25 \\ \text{Hypo}=\sqrt[]{25} \\ \text{Hypo}=\text{ 5} \end{gathered}

The Perimeter of a triangle = a+b+c

The perimeter of a triangle = 3+4+5

The perimeter of a triangle = 12

The perimeter of the base =12

2. Height of the prism = 6

3.


\begin{gathered} \text{Area of the base (triangle) =}(1)/(2)bh \\ \text{Where b is the base } \\ h\text{ is the height} \\ b=4\text{ and h=3} \\ \text{Area of the base (triangle) =}(1)/(2)*4*3 \\ \\ \\ \text{Area of the base (triangle) =}(1)/(2)*12 \\ \\ \text{Area of the base (triangle)}=6\text{ squared unit} \\ \end{gathered}

4. Lateral Area= (a+b+c)h

Lateral Area= (3+4+5)6

Lateral Area= (12)6

Lateral Area= 72 squared unit

5. Surface area

6. Volume

Volume is 36 cubic units

63Perimeter of the base =Height of the prism =Area of the base =Lateral Area =u2Surface-example-1
63Perimeter of the base =Height of the prism =Area of the base =Lateral Area =u2Surface-example-2
63Perimeter of the base =Height of the prism =Area of the base =Lateral Area =u2Surface-example-3
User Borealis
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