First, find the number of moles it must contain.
![c=(n)/(V)](https://img.qammunity.org/2023/formulas/chemistry/college/7kwahldt2uhg219tjyggizmlcs3t04ila8.png)
Where n is the number of moles, c = 0.5 and V = 600 mL. But, we need to use the volume in Liters, so we divide 600mL by 1000.
![V=600mL(1L)/(1000mL)=0.6L](https://img.qammunity.org/2023/formulas/chemistry/college/istd4hbuy5ae59j59tn1qvav0iz6l5f1tu.png)
Once we have the correct unit, find n.
![n=0.5\cdot(mol)/(L)\cdot0.6L=0.3\text{moles}](https://img.qammunity.org/2023/formulas/chemistry/college/3vyxaozht5zm8l45t0x1qrd3ychb5jwy7i.png)
Now, we need to know what volume would contain 0.3 moles, using the same formula.
![V=(n)/(c)](https://img.qammunity.org/2023/formulas/chemistry/college/4rnxgz5po8c8k32qobe1gvln5uxeakrfwf.png)
Where n = 0.3 moles and c = 1.2 mol/L.
![V=\frac{0.3\text{moles}}{1.2\cdot(moles)/(L)}=0.25L](https://img.qammunity.org/2023/formulas/chemistry/college/ol7g1yqirwmc60nripjria6ifav4aorz5f.png)
At last, transform 0.25 Liters into mL.
![V=0.25L\cdot(1000mL)/(1L)=250mL](https://img.qammunity.org/2023/formulas/chemistry/college/uaj2a8amllnkk1vlh5quqd82zww2979m39.png)
Therefore, the volume is 250 mL.