In order to find the value of sin x°, first let's draw the triangle. We also need to know that the tangent relation is equal to the opposite leg over the adjacent leg, and the cosine is the adjacent leg over the hypotenuse.
So we have:
This way, we can find the sine, which is equal to the opposite leg over the hypotenuse:
![\sin x°=(3)/(z)](https://img.qammunity.org/2023/formulas/physics/high-school/zgz9q8vvzx3uvh6p8mmxka45n5xsddsk4f.png)
Therefore the correct option is the first one.