Question

base your answer to the question on the information given. a 1,000-kilogram car traveling with a velocity of 20 meters per second decelerates uniformly at -5.0 meters per second^2 until it comes to rest. what is the total distance the car travels as it decelerates to rest?

Answer 1

40 meters

Step-by-step explanation:

To solve this, we will use the motion formula
`v^(2) =u^(2) +2as`, where v is the final speed, u is the initial speed, a is the acceleration, and s is the distance. We know:

u= 20m/s

a= - 5m/s^2 (note the minus sign because we are decelerating)

v= 0m/s (our final speed will be 0 because we want to come to a stop)

Now plug in these values into the formula:

`v^(2) =u^(2) +2as`

`0^(2) =20^(2) +2(-5)s`

`0 =400-10s`

`10s=400`

`s=40\\`