Step-by-step explanation:
Given;
We are told that a deposit of $2000 is invested in an account that yields an annual interest of 4.5%, but is compounded monthly.
Required;
We are required to calculate how much money will be in the investment in 6 years time.
Step-by-step solution.
The formula for calculating a compound interest is given as;
![A=P(1+r)^t](https://img.qammunity.org/2023/formulas/mathematics/college/oore8x40g44yuigz8li3pepnuow1o5picv.png)
The variables in this formula are;
![\begin{gathered} A=amount\text{ }after\text{ }the\text{ }period\text{ }given \\ P=principal\text{ }amount\text{ }at\text{ }the\text{ }beginning \\ r=annual\text{ }rate\text{ }of\text{ }interest \\ t=period\text{ }of\text{ }investment\text{ }in\text{ }years \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/kczhxztsq08mn0wclfcbu830c6dsf358pw.png)
However, when the compounding is done at several periods within a year (for example, monthly, quarterly, half-yearly, etc), the formula is amended to reflect the period of compounding within each year.
The amended formula is what we have been given in this question.
Therefore, from the details provided,
![\begin{gathered} P=2000 \\ r=0.045 \\ t=6 \\ n=12 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/kshmktz2nevog03rwwy2xpedn9nnbf8zci.png)
Please note that n is the number of times compounding takes place per year and in this case its 12 times (monthly).
Therefore;
![A=2000(1+(0.045)/(12))^(12*6)](https://img.qammunity.org/2023/formulas/mathematics/college/34l1mb55qjo3z66pdt5y4m848te9l98uyc.png)
![\begin{gathered} A=2000(1+0.00375)^(72) \\ \\ A=2000(1.00375)^(72) \\ \\ A=2000*1.30930310151 \\ \\ A=2618.60620301 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/sxf4wo80rpc8isjpzrfhkwyytgqqm5bdiy.png)
Rounded to the nearest hundredth, we now have
ANSWER:
![A=2,618.61](https://img.qammunity.org/2023/formulas/mathematics/college/z5aonrtjcw2bw10s4hetd3thqtqxd8fjo2.png)