Question

BIG IDEAS MATH hapter 5: Comparing and Graphing Ratios > Section Exercises 5.4 > Exercise 16 A chemist prepares two acid solutions. a. Use a ratio table to determine which solution is more acidic. Solution 1 Solution 2 Water Sulfuric Acid Sulfuric Acid Water 7 HT 9 5 CA 2015 21 18 42 45 SOLUTION 1 3 parts sulfuric acid to 7 parts water SOLUTION 2 4 parts sulfuric acid to 9 parts water 63 63

Answer 1

the Given the initial ratio of the sulfuric acid to water

`\begin{gathered} \text{Solution 1}\Rightarrow\text{ 3 : 7 } \\ \text{Solution 2}\Rightarrow\text{ 4 : 9} \end{gathered}`

So to obtain the ratio value of the sulfuric in solution 1, multiply each water ratio by 3/7

`\begin{gathered} 7\Rightarrow\text{ 7}*(3)/(7)=(21)/(7)\text{ = 3} \\ 21\Rightarrow\text{ 21}*(3)/(7)=3*3=6 \\ 42\Rightarrow\text{ 42}*(3)/(7)=6*3=18 \\ 63\Rightarrow63*(3)/(7)=9*3=27 \end{gathered}`

So to obtain the ratio value of the sulfuric in solution 2, multiply each water ratio by 4/9

`\begin{gathered} 9\Rightarrow9*(4)/(9)=1*4=4 \\ 18\Rightarrow18*(4)/(9)=2*4=8 \\ 45\Rightarrow45*(4)/(9)=5*4=20 \\ 63\Rightarrow63*(4)/(9)=7*4=28 \end{gathered}`

In conclusion, you will notice that when solution 1 has a water ratio of 63, the acidic content is 27, while in solution 2 when water ratio is 63 the acidic content is 28.

Hence, Solution 2 is more acidic