Question

Write an equation for the line described. Give the answer in standard form.through (6,2), m= -5The equation of the line is

Answer 1

Given:

The slope of line, m=-5.

The line passes through point (x1, y1)=(6,2).

The point-slope form of the equation of a line can be expressed as,

`(y-y1)/(x-x1)=m`

Now, put the values of x1, y1 and m in the above equation to find the equation of the line.

`\begin{gathered} (y-2)/(x-6)=-5 \\ y-2=-5(x-6) \\ y-2=-5x-5*(-6) \\ y-2=-5x+30 \\ y=-5x+30+2 \\ y=-5x+32 \end{gathered}`

Therefore, the equation of the line passing through (6,2) and having slope, m=-5, is y=-5x+32.