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Find the area of each figure. Round to the hundredths where necessary. 11 in 7 in 8.1 in 15 in

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we are asked to determine the area of the following figure:

we have divided the figure into a rectangle and a triangle. The total area is the sum of the areas of both figures. First, we will find the area of the rectangle:


\begin{gathered} A_1=(7in)(11in) \\ A_1=77in^2 \end{gathered}

Now we will find the area of the triangle using the following formula:


A_2=(bh)/(2)

Where "b" is the base and "h" is the height. The base is found by subtracting the dimension on top to the dimension of the bottom:


b=15in-11in=4in

Now we will use the formula:


A_2=((4in)(7in))/(2)

Solving the operations:


A_2=14in^2

Now we add both areas:


\begin{gathered} A=A_1+A_2 \\ A=77in^2+14in^2 \\ A=91in^2 \end{gathered}

Therefore, the area of the figure is 91 square inches.

Find the area of each figure. Round to the hundredths where necessary. 11 in 7 in-example-1
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