Question

A(n) = 60 • 3(n-1)How many bacteria are in generation 9?

Answer 1

The number of bacteria in the generation 9 can be determined as,

`\begin{gathered} a(n)=60*3^((n-1)) \\ a(9)=60*3^((9-1)) \\ =60*3^8 \\ =393660 \end{gathered}`

Thus, option (A) is correct.