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Raising 145kg, 21600j of work. How high is it raised?

User RBreuer
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1 Answer

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Given,

The mass, m=145 kg

The work done, W=21600 J

The work is the measure of energy transfer through the application of external force to move an object.

The work done is given by,


W=\Delta PE=mg\Delta h

Where ΔPE is the potential energy, g is the acceleration due to gravity, and Δh is the change in the height of the object.

On rearranging the above equation,


\Delta h=(W)/(mg)

On substituting the known values,


\begin{gathered} \Delta h=(21600)/(145*9.8) \\ =15.2\text{ m} \end{gathered}

Thus the object was raised through a height of 15.2 m

User Jose Marin
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