Answer:
Square A'B'C'D' is the image of ABCD after a reflection and a translation
Step-by-step explanation:
Given the quadrilateral ABCD, with coordinates;
![(-2,9),(-7,9),(-7,4),(-2,4)](https://img.qammunity.org/2023/formulas/mathematics/high-school/i7j6541o2f05m92h69e45smdd0deqbkfv2.png)
From the given image A'B'C'D', the size of the image and that of the pre-image is the same so, there is no dilation since there is no change in size.
Looking at the orientation of the image, we can observe the pre-image was reflected across the x-axis;
![(x,y)\rightarrow(x,-y)](https://img.qammunity.org/2023/formulas/mathematics/college/d7a29ae1nc5itoub5zbvfqbwxpczq9rzr6.png)
Looking further, we can see that there has been a shift in the position of the image after the reflection. So, there is also a translation after the reflection.
Therefore, Square A'B'C'D' is the image of ABCD after a reflection and a translation