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For a sample size of 90 and a sample proportion of 0.5, what is the standarderror of the sampling distribution? Round your answer to three decimalplaces.A. 0.045B. 0.039C. 0.064D. 0.053

User Linusz
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The standard error can be found by using the expression:


\begin{gathered} SE_p=\sqrt[]{(p(1-p))/(n)} \\ SE_p=\sqrt[]{(0.5\cdot(1-0.5))/(90)} \\ SE_p=\sqrt[]{(0.5\cdot0.5)/(90)} \\ SE_p=\sqrt[]{(0.25)/(90)} \\ SE_p=\sqrt[]{0.0027777777777778} \\ SE_p=0.053 \end{gathered}

The answer is D.

User Yspreen
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