Consider the property of exponents,

The expression is given as,
![(\sqrt[]{s})^2](https://img.qammunity.org/2023/formulas/mathematics/college/1sytslxumghdry0s37guoemsc9uovvnr7q.png)
The square root operation is nothing but an exponent 1/2.
![\sqrt[]{x}=x^{(1)/(2)}](https://img.qammunity.org/2023/formulas/mathematics/college/qs7vpqo09ne5jtgklc0yiwbw2nxtgclx0u.png)
Then the given expression can be resolved as,
![(\sqrt[]{s})^2=(s^{(1)/(2)})^2=(s)^{(1)/(2)\cdot2}=s^1=s^{}](https://img.qammunity.org/2023/formulas/mathematics/college/4b6ja6x36c3da77syx4j8iv5d7eae3qgil.png)
Thus, the given expression can be written as,
![(\sqrt[]{s})^2=s](https://img.qammunity.org/2023/formulas/mathematics/college/sbvseqhtjdvzft363mqqiysz25spjwgxap.png)
Therefore, option C is the correct choice.